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0.8x^2-1.2=-1
We move all terms to the left:
0.8x^2-1.2-(-1)=0
We add all the numbers together, and all the variables
0.8x^2-0.2=0
a = 0.8; b = 0; c = -0.2;
Δ = b2-4ac
Δ = 02-4·0.8·(-0.2)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.64}}{2*0.8}=\frac{0-\sqrt{0.64}}{1.6} =-\frac{\sqrt{}}{1.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.64}}{2*0.8}=\frac{0+\sqrt{0.64}}{1.6} =\frac{\sqrt{}}{1.6} $
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